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9a^2+8=278
We move all terms to the left:
9a^2+8-(278)=0
We add all the numbers together, and all the variables
9a^2-270=0
a = 9; b = 0; c = -270;
Δ = b2-4ac
Δ = 02-4·9·(-270)
Δ = 9720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9720}=\sqrt{324*30}=\sqrt{324}*\sqrt{30}=18\sqrt{30}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{30}}{2*9}=\frac{0-18\sqrt{30}}{18} =-\frac{18\sqrt{30}}{18} =-\sqrt{30} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{30}}{2*9}=\frac{0+18\sqrt{30}}{18} =\frac{18\sqrt{30}}{18} =\sqrt{30} $
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